题目

求AX+BY=C的x,y，若无解，输出-1

题目链接：https://codeforces.com/contest/7/problem/C

代码

#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<cctype>
#include<ctime>
#include<iostream>
#include<string>
#include<map>
#include<queue>
#include<stack>
#include<set>
#include<vector>
#include<iomanip>
#include<list>
#include<bitset>
#include<sstream>
#include<fstream>
#include<complex>
#include<algorithm>
#if __cplusplus >= 201103L
#include <unordered_map>
#include <unordered_set>
#endif
#define ll long long
//#define int long long
using namespace std;
const int INF = 0x3f3f3f3f;
ll gcd=0;
ll exgcd(ll a,ll b,ll &x,ll &y){
	if(b==0){
		x=1;
		y=0;
		return a;
	}
	ll g=exgcd(b,a%b,x,y);
	ll temp=x;
	x=y;
	y=temp-(a/b)*y;
	//cout<<x<<" "<<y<<endl;
	return g;
}
int main(){
	ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
	ll a,b,c;
	cin>>a>>b>>c;
	ll x=0,y=0;
	gcd=exgcd(a,b,x,y);
	if(c%gcd!=0) cout<<-1<<endl;
	else{
		cout<<-x*c/gcd<<" "<<-y*c/gcd<<endl;
	}
    return 0;
}